Decide who's going to eat pizza, and how much they could eat.
Step Two:
Determine sizes:
diameter = 2r
PI = 3.14
area_of_pizza = PIr^2
| Diameter | Area (square inches) |
|---|---|
| 9 | 63.585 |
| 12 | 113.04 |
| 15 | 176.625 |
| 18 | 254.34 |
People:
person_consumption = quantity * PIr2
| Person | QTY | Size | Square Inches |
| James | 1 | 12 | 113.04 |
| Kevin | 1.25 | 12 | 141.3 |
| Laurie | 0.75 | 12 | 84.78 |
| Yuxin | 0.75 | 12 | 84.78 |
| Dan | 1 | 12 | 113.04 |
| Vandana | 0.5 | 12 | 56.52 |
| Vishal | 1 | 9 | 63.585 |
| Nick | 0.5 | 12 | 56.52 |
| Robby | 0.75 | 12 | 84.78 |
| Jo | 0.75 | 12 | 84.78 |
| Sven | 0.75 | 12 | 84.78 |
Total Consumption = 883.125, Average: 80.2
Question:
Do we get either:
3 * 18 inch + 1 * 15 inch
3 * 18 inch + 12 inch
And which one do we make (an 18 or 15 inch) a vegetarian (Vandana/Vishal require this)?
Proposed Solution:
* Feed Vandana + Vishal first and foremost of a 15 inch family pizza
* Everyone else fights tooth and nail for the remained
3 Party 763.02
1 Family 176.625
Total: 939.645
3 Party 763.02
1 Large 113.04
Total: 876.06
result = 3*18 inch + 15 inch pizza; // 939.645
leftovers = result - total_consumption; // 939.645 - 883.125 = ~56 square inches of leftover pizza.
Assuming crust and extra hungryness, we should be bang on target!
Results after lunch
